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Question Number 211659 by efronzo1 last updated on 15/Sep/24
Commented by Frix last updated on 15/Sep/24
Simplytransformit⇒n=3
Answered by BHOOPENDRA last updated on 15/Sep/24
5+n3−22=(5+2)(15+3−10−6)5+n3−22=33−22+5comparebothsiden=3
Answered by a.lgnaoui last updated on 15/Sep/24
5+n3−22=(5+3)(5+2)(.3−2)=[5+10+15+6)](3−2)==53−52+30−25+35−30+32−23=33+5−22⇒5+n3−22=5+33−22n=3
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