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Question Number 211861 by hardmath last updated on 22/Sep/24
ab―+ba―=4ca+b+3c=?
Answered by A5T last updated on 22/Sep/24
10a+b+10b+a=11(a+b)=4ca+b=4k⩽9+9=18⇒k⩽4⇒44k=4c⇒c=11k⩽44⇒c∈(11,22,33,44)whenc=11;a+b=4⇒a+b+3c=37whenc=22;a+b=8⇒a+b+3c=74whenc=33;a+b=12⇒a+b+3c=111whenc=44;a+b=16⇒a+b+3c=148
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