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Question Number 211881 by Spillover last updated on 23/Sep/24

Answered by som(math1967) last updated on 23/Sep/24

 α+β+γ=1,αβ+βγ+γα=−2   αβγ=−1   α^2 +β^2 +γ^2 =1+4=5  ^3 (√(α^6 /(α^2 β^2 γ^2 )))+^3 (√(β^6 /(α^2 β^2 γ^2 )))+^3 (√(γ^6 /(α^2 β^2 γ^2 )))  =(α^2 /1)+(β^2 /1)+(γ^2 /1)  =(α^2 +β^2 +γ^2 )=5

α+β+γ=1,αβ+βγ+γα=2αβγ=1α2+β2+γ2=1+4=53α6α2β2γ2+3β6α2β2γ2+3γ6α2β2γ2=α21+β21+γ21=(α2+β2+γ2)=5

Commented by Spillover last updated on 23/Sep/24

correct.thanks

correct.thanks

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