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Question Number 211881 by Spillover last updated on 23/Sep/24
Answered by som(math1967) last updated on 23/Sep/24
α+β+γ=1,αβ+βγ+γα=−2αβγ=−1α2+β2+γ2=1+4=53α6α2β2γ2+3β6α2β2γ2+3γ6α2β2γ2=α21+β21+γ21=(α2+β2+γ2)=5
Commented by Spillover last updated on 23/Sep/24
correct.thanks
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