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Question Number 211979 by Spillover last updated on 25/Sep/24

Answered by BHOOPENDRA last updated on 25/Sep/24

$$\int \frac{dx}{(x^2{\tan }^{-1}x+{\tan }^{-1}x+x^2\pi +\pi )}$$$$\int \frac{dx}{(x^2+1)({\tan }^{-1}x+\pi )}$$$$Lett={\tan }^{-1}x+\pi$$$$dt=\frac{dx}{1+x^2}$$$$\int \frac{1}{t}dt=ln\left(t\right)$$$$putt=({\tan }^{-1}x+\pi )$$$$ln({\tan }^{-1}x+\pi )+c$$

Commented by Spillover last updated on 26/Sep/24

$$great.thanks$$

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