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Question Number 212053 by universe last updated on 28/Sep/24

$$$$$${\int }_0^1\left({\int }_0^{\mathit{y}}{\mathit{e}}^{{\mathit{x}}^2+{\mathit{y}}^2}\mathit{d}\mathit{x}\right)\mathit{d}\mathit{y}+{\int }_1^2\left({\int }_0^{2-\mathit{y}}{\mathit{e}}^{{\mathit{x}}^2+{\mathit{y}}^2}\mathit{d}\mathit{x}\right)\mathit{d}\mathit{y}=?$$$$$$

Answered by MrGaster last updated on 03/Nov/24

$$={\int }_0^1{\int }_0^y\left(e^{x^2+y^2}dx\right)dy+{\int }_1^2\left({\int }_0^{2-y}{e}^{x^2+y^2}dx\right)dy$$$$={\int }_0^1{\int }_0^y{e}^{x^2+y^2}dxdy+{\int }_1^2{\int }_0^{2-y}{e}^{x^2-y^2}dxdy\dots$$

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