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Question Number 212067 by Spillover last updated on 28/Sep/24

Answered by Spillover last updated on 28/Sep/24

Commented by Ghisom last updated on 28/Sep/24

$${\mathrm{that}}^{\prime }\mathrm{s}\mathrm{not}\mathrm{true}.\mathrm{we}\mathrm{can}\mathrm{solve}\mathrm{the}\mathrm{equation}$$$$\mathrm{for}y:$$$$y=\frac{x^4-\frac{1189}{360}{x}^3+3x^2-\frac{1189}{180}x+1}{x^5-\frac{1188}{360}{x}^4+4x^3-\frac{1189}{120}{x}^2+3x-\frac{1189}{360}}$$$$\mathrm{and}\mathrm{plug}\mathrm{in}\mathrm{any}\mathrm{value}\mathrm{for}x\mathrm{except}\mathrm{the}$$$$\mathrm{zero}\mathrm{of}\mathrm{the}\mathrm{denominator}\mathrm{which}\mathrm{is}\mathrm{very}$$$$\mathrm{close}\mathrm{to}3(x\approx 3+\frac{1}{35947})$$$$\mathrm{we}\mathrm{get}.49<P<\mathrm{\infty }$$$$(\mathrm{minimum}\mathrm{at}x\approx 1.47520852,$$$$y\approx .497303672,P\approx .490429398)$$$$x=3\Rightarrow y=3\mathrm{is}\mathrm{maybe}\mathrm{the}\mathrm{only}\mathrm{solution}$$$$\mathrm{which}\mathrm{makes}\mathrm{sense}.$$

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