sin^2 1^o + sin^2 5^o + sin^2 9^o + ... sin^2 89^o = a (1/b) b = ? Help me, please


Question and Answers Forum

All Questions Topic List
None Questions
Previous in All Question Next in All Question
Previous in None Next in None
Question Number 212186 by Ismoiljon_008 last updated on 05/Oct/24

${s i n}^{2} 1^{o} + {s i n}^{2} 5^{o} + {s i n}^{2} 9^{o} + . . . {s i n}^{2} 89^{o} = a \frac{1}{b}$ $b = ?$ $H e l p m e, p l e a s e$
	Answered by mehdee7396 last updated on 05/Oct/24

	$s^{2} 1 + s^{2} 5 + s^{2} 9 + . . . + s^{2} 41 + s^{2} 45 + c^{2} 41 + . . . + c^{2} 9 + c^{2} 5 + c^{2} 1 =$ $11 + \frac{1}{2} = a \frac{1}{b} \Rightarrow b = 2 ✓$
	Commented by Ismoiljon_008 last updated on 05/Oct/24

	$T h a n k y o u v e r y m u c h$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum