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Question Number 212314 by Spillover last updated on 09/Oct/24
Answered by mehdee7396 last updated on 09/Oct/24
f(x)=ln(2−sinx2+sinx)f(−x)=ln(2+sinx2−sinx)=−f(x)⇒;f;is;odd⇒∫−π2π2f(x)dx=0✓
Answered by Ghisom last updated on 09/Oct/24
f(x)=ln2−sinx2+sinxf(−x)=ln2+sinx2−sinx=−ln2−sinx2+sinx=−f(x)⇒∫a−af(x)dx=0
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