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Question Number 212327 by MASANJAJJ last updated on 10/Oct/24

if (a+(1/a))=15 find the value of (a^2  +(1/a^2 ))

if(a+1a)=15findthevalueof(a2+1a2)

Answered by universe last updated on 10/Oct/24

(a+(1/a))^2  = 15^2   a^2 +(1/a^2 ) +2 = 225  a^2 +(1/a^2 ) = 225−2 = 223

(a+1a)2=152a2+1a2+2=225a2+1a2=2252=223

Answered by mehdee7396 last updated on 10/Oct/24

(a+(1/a))^2 =225⇒a^2 +(1/a^2 )=223 ✓

(a+1a)2=225a2+1a2=223

Answered by Rasheed.Sindhi last updated on 10/Oct/24

Another way  a+(1/a)=15 ; a^2 +(1/a^2 )=?  a+(1/a)=15⇒a^2 =15a−1  ⇒(1/a)=15−a⇒(1/a^2 )=a^2 −30a+225  =15a−1−30a+225=224−15a     a^2 +(1/a^2 )=(15a−1)+(224−15a)=223

Anotherwaya+1a=15;a2+1a2=?a+1a=15a2=15a11a=15a1a2=a230a+225=15a130a+225=22415aa2+1a2=(15a1)+(22415a)=223

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