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Question Number 212360 by MrGaster last updated on 11/Oct/24

$$$$$$T=\underset{n=0}{\sum ^{\mathrm{\infty }}}(\frac{1}{{(4n+1)}^2}-\frac{1}{{(4n+3)}^2}$$

Answered by Berbere last updated on 15/Oct/24

$$=\sum _{n⩾0}\frac{{(-1)}^n}{{(2n+1)}^2}=Ccatalaneconstante$$

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