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Question Number 212405 by mathlove last updated on 13/Oct/24
limx→3ex−e3x−3=?
Answered by som(math1967) last updated on 13/Oct/24
limx→3e3(ex−3−1)(x−3)=e3lima→0ea−1ea[letx−3=a∵x→3∴(x−3)→0∴a→0]=e3×1=e3
Commented by mathlove last updated on 13/Oct/24
thankssir
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