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Question Number 212424 by hardmath last updated on 13/Oct/24

$$\{\begin{array}{l}\mathrm{x}+2\mathrm{y}-3\mathrm{z}=1\\ 2\mathrm{x}-\mathrm{y}+\mathrm{z}=4\\ 3\mathrm{x}+\mathrm{y}+2\mathrm{z}=7\end{array}\mathrm{find}:\mathrm{x},\mathrm{y},\mathrm{z}=?$$

Answered by A5T last updated on 13/Oct/24

$$\left(ii\right)+\left(iii\right)\Rightarrow 5x+3z=11...\left(iv\right)$$$$2\left(iii\right)-\left(i\right)\Rightarrow 5x+7z=13...\left(v\right)$$$$\left(v\right)-\left(iv\right)\Rightarrow 4z=2\Rightarrow z=\frac{1}{2}\Rightarrow x=\frac{19}{10}\Rightarrow y=\frac{3}{10}$$$$(x,y,z)=(1.9,0.3,0.5)$$

Commented by hardmath last updated on 13/Oct/24

$$\mathrm{thank}\mathrm{you}\mathrm{dear}\mathrm{professor}$$

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