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Question Number 212479 by hardmath last updated on 14/Oct/24

$$\{\begin{array}{l}2\mathrm{x}+3\mathrm{y}-\mathrm{z}=7\\ 4\mathrm{x}-\mathrm{y}+2\mathrm{z}=1\\ -\mathrm{x}+5\mathrm{y}+3\mathrm{z}=14\end{array}\mathrm{find}:\mathrm{x},\mathrm{y},\mathrm{z}=?$$

Answered by A5T last updated on 14/Oct/24

$$3\left(ii\right)+\left(i\right)\Rightarrow 14x+5z=10...\left(iv\right)$$$$5\left(ii\right)+\left(iii\right)\Rightarrow 19x+13z=19...\left(v\right)$$$$13\left(iv\right)-5\left(v\right)\Rightarrow 87x=35\Rightarrow x=\frac{35}{87}\Rightarrow z=\frac{76}{87}\Rightarrow y=\frac{205}{87}$$

Commented by hardmath last updated on 14/Oct/24

$$\mathrm{thankyou}\mathrm{dearprofessor}$$

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