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Question Number 212496 by efronzo1 last updated on 15/Oct/24

$$\mathrm{If}1.1!+3.2!+...+(2\mathrm{n}-1).\mathrm{n}!$$$$=\mathrm{a}.(\mathrm{n}+1)!+\mathrm{b}(1!+2!+...+(\mathrm{n}+1)!)+\mathrm{c}$$$$\mathrm{for}\mathrm{a},\mathrm{b},\mathrm{c}\mathrm{integers}\mathrm{number}$$$$\mathrm{find}2\mathrm{a}-\mathrm{b}+3\mathrm{c}$$

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