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Question Number 212646 by MrGaster last updated on 20/Oct/24
limn→∞∑ni=1∑ij=ii(i+j)(n2+i2)(n2+j2)
Commented by mr W last updated on 21/Oct/24
∑ij=1.....
Answered by MrGaster last updated on 31/Oct/24
limn→∞∑ni=12i2(n2+i2)2limn→∞1n∑ni=12(in)2(1+(in)2)⋅1n∫012x2(1+x2)2dx[−x1+x2+arctan(x)]01−12+π4
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