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Question Number 212651 by hardmath last updated on 20/Oct/24

Answered by Ghisom last updated on 20/Oct/24

$$x+3y+5z⩽15$$$$x+y+z⩽7$$$$2x+y+4z⩽12$$$$========$$$$x+3y+5z⩽15$$$$y+2z⩽4$$$$5y+6z⩽18$$$$========$$$$x+3y+5z⩽15$$$$y+2z⩽4$$$$z⩽\frac{1}{2}$$$$========$$$$x⩽\frac{7}{2}$$$$y⩽3$$$$z⩽\frac{1}{2}$$$$========$$$$2x+3y+z⩽\frac{33}{2}$$

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