Question and Answers Forum

All Questions      Topic List

Geometry Questions

Previous in All Question      Next in All Question      

Previous in Geometry      Next in Geometry      

Question Number 212668 by Spillover last updated on 20/Oct/24

Answered by efronzo1 last updated on 21/Oct/24

$${\mathrm{BC}}^2=64+25-40=49$$$${\mathrm{BC}}^2={2\mathrm{r}}^2+{\mathrm{r}}^2\Rightarrow \mathrm{r}=\sqrt{\frac{{\mathrm{BC}}^2}{3}}=\frac{7\sqrt{3}}{3}$$

Commented by Spillover last updated on 21/Oct/24

$$good$$

Answered by mr W last updated on 21/Oct/24

$$R=\frac{BC}{2\sin A}$$$$=\frac{\sqrt{8^2+5^2-2\times 8\times 5\cos 60°}}{2\sin 60°}=\frac{7}{\sqrt{3}}\approx 4$$

Commented by Spillover last updated on 21/Oct/24

$$good$$

Answered by Spillover last updated on 21/Oct/24

Answered by Spillover last updated on 21/Oct/24

$$$$X²=8²+5²-2•8•5cos60 X²=64+25-40 X²=49 X=7 7²=R²+R²+2R²cos60 49=3R² 7=R√3 R=7√3/3

Terms of Service

Privacy Policy

Contact: info@tinkutara.com