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Question Number 212719 by Spillover last updated on 22/Oct/24

Answered by A5T last updated on 22/Oct/24

Commented by A5T last updated on 22/Oct/24

a=2((π/6)−((sin60°)/2))=2((π/6)−((√3)/4))=(π/3)−((√3)/2)  A=(π/2)−((2π)/3)+(√3)=(√3)−(π/6)  [Non-shaded]=6A+6a=3(√3)+π  [Hexagon]=6×2×((√3)/2)=6(√3)  [Shaded]=6(√3)−3(√3)−π=3(√3)−π

a=2(π6sin60°2)=2(π634)=π332A=π22π3+3=3π6[Nonshaded]=6A+6a=33+π[Hexagon]=6×2×32=63[Shaded]=6333π=33π

Commented by Spillover last updated on 23/Oct/24

great work.thanks

greatwork.thanks

Answered by Spillover last updated on 25/Oct/24

Answered by Spillover last updated on 25/Oct/24

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