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Question Number 21276 by ketto last updated on 18/Sep/17
Answered by $@ty@m last updated on 19/Sep/17
(a)Givent3=18⇒ar2=18−−(1)t5=162⇒ar4=162−−(2)Dividing(2)by(1)r2=9⇒r=±3∴from(1)a=2(b)Givent8=t5+9⇒a+7d=a+4d+9⇒d=3andt10=10t2⇒a+9d=10(a+d)⇒a+9d=10a+10d⇒−9a=d⇒−9a=3⇒a=−13
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