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Question Number 212829 by mr W last updated on 25/Oct/24

Commented by mr W last updated on 25/Oct/24

find the total area of the rectangle.

findthetotalareaoftherectangle.

Answered by ajfour last updated on 25/Oct/24

let   ((4+A)/(12))=(p/q)  y=((h/p))x    &  y=−((h/(p+q)))(x−p−q)  ⇒  ((hx)/p)((q/(p+q)))=h  ⇒   x=(((p+q)p)/q)  Now  (A/4)=(x/p)=(p/q)+1  ⇒  ((A−4)/4)=((4+A)/(12))  3A−12=4+A  A=8  rectangle area = 2(A+4+12)      =2×24=48 sq units.

let4+A12=pqy=(hp)x&y=(hp+q)(xpq)hxp(qp+q)=hx=(p+q)pqNowA4=xp=pq+1A44=4+A123A12=4+AA=8rectanglearea=2(A+4+12)=2×24=48squnits.

Answered by A5T last updated on 25/Oct/24

Commented by A5T last updated on 25/Oct/24

A+4=4+B⇒A=B  A+C=4+B+12⇒C=16  (A/4)=(C/B)⇒A^2 =4C=64⇒A=8  [rectangle]=8+8+16+12+4=48

A+4=4+BA=BA+C=4+B+12C=16A4=CBA2=4C=64A=8[rectangle]=8+8+16+12+4=48

Answered by Spillover last updated on 25/Oct/24

Answered by Spillover last updated on 25/Oct/24

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