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Question Number 212935 by MrGaster last updated on 27/Oct/24
Proving:∣∫01f(x)dx−f(0)+f(1)2∣⩽132
Answered by mehdee7396 last updated on 27/Oct/24
forexamplef(x)=x2⇒∫01f(x)dx=13⇒∣∫01f(x)dx−f(0)+f(1)2∣=16⪇132?
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