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Question Number 212991 by efronzo1 last updated on 28/Oct/24

$$\underbrace{\downharpoonleft \underset{―}{}}$$

Answered by Frix last updated on 28/Oct/24

$$H\left(n\right)=\underset{k=1}{\sum ^n}k!(k^2+k+1)$$$$\frac{H\left(n\right)+1}{(n+1)!}=n+1[\mathrm{test}\mathrm{it}\mathrm{for}n=1,2,3,...]$$$$\Rightarrow \mathrm{answer}\mathrm{is}2026$$

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