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Question Number 213099 by MathematicalUser2357 last updated on 30/Oct/24

$$\frac{1}{2}(x-1)-(x-3)=\frac{1}{3}(x+3)+\frac{1}{6}$$$$x=...$$

Answered by MrGaster last updated on 30/Oct/24

$$\frac{1}{2}x-\frac{1}{2}-x+3=\frac{1}{3}x+1+\frac{1}{6}$$$$-\frac{1}{2}x+\frac{5}{2}=\frac{1}{3}x+\frac{7}{6}$$$$-\frac{1}{2}x-\frac{1}{3}x=\frac{7}{6}-\frac{5}{2}$$$$-\frac{3}{6}x-\frac{2}{6}x=-\frac{4}{6}$$$$-\frac{5}{6}x=\frac{8}{6}$$$$x=\frac{-\frac{8}{6}}{-\frac{5}{6}}$$$$x=\frac{8}{5}$$

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