we can find tan120 by tan(180−60) but can not find by tan(90+30) why?


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Question Number 213175 by Davidtim last updated on 31/Oct/24

$w e c a n f i n d t a n 120 b y t a n (180 - 60)$ $b u t c a n n o t f i n d b y t a n (90 + 30) w h y ?$
	Answered by efronzo1 last updated on 31/Oct/24

	$\tan 120 ° = \tan (90 ° + 30 °) = - \cot 30 ° = - \sqrt{3}$
	Answered by MATHEMATICSAM last updated on 31/Oct/24

	$You can find by both$ $\tan (180 ° - 60 °) = - \tan 60 ° = - \sqrt{3}$ $\tan (90 ° + 30 °) = - \cot 30 ° = - \sqrt{3}$
	Answered by MrGaster last updated on 31/Oct/24

	$\tan (180 - 60) = \tan 60 = - \sqrt{3}$ $\tan (90 + 30) = \frac{\sin (90 + 30)}{\cos (90 + 30)} = \frac{\cos 30}{- \sin 30} = \frac{\sqrt{3} / 2}{- 1 / 2} = - \sqrt{3}$
	Answered by a.lgnaoui last updated on 01/Nov/24

	$becsuse \cos 90 = 0 and \tan 90 not determined$
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