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Question Number 213322 by Spillover last updated on 02/Nov/24

Commented by Spillover last updated on 03/Nov/24

Answered by Spillover last updated on 03/Nov/24

Answered by A5T last updated on 02/Nov/24

Commented by A5T last updated on 02/Nov/24

$$R=3+1+2=6$$

Commented by Spillover last updated on 02/Nov/24

$$yes.great$$

Answered by mr W last updated on 02/Nov/24

$${(\frac{1}{1}+\frac{1}{2}+\frac{1}{3}-\frac{1}{R})}^2=2(\frac{1}{1^2}+\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{R^2})$$$$\frac{1}{R^2}+\frac{11}{3R}-\frac{23}{36}=0$$$$\Rightarrow \frac{1}{R}=\frac{1}{2}(-\frac{11}{3}+\frac{12}{3})=\frac{1}{6}\Rightarrow R=6$$

Commented by mr W last updated on 03/Nov/24

$$yes$$

Commented by Spillover last updated on 03/Nov/24

$$great$$

Commented by efronzo1 last updated on 03/Nov/24

$$\mathrm{Descartes}\mathrm{Formula}?$$

Answered by mehdee7396 last updated on 02/Nov/24

$$R=3+3=6$$

Commented by Spillover last updated on 03/Nov/24

$$good$$

Commented by mehdee7396 last updated on 02/Nov/24

Commented by TonyCWX08 last updated on 03/Nov/24

$$Byfarthebestsolution....$$

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