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Question Number 213664 by 281981 last updated on 13/Nov/24

Answered by mr W last updated on 13/Nov/24

Commented by mr W last updated on 13/Nov/24

$$\frac{x}{20-y}=\frac{5}{y}$$$$x=\frac{100}{y}-5$$$$u=\frac{dx}{dt}=-\frac{100}{y^2}\times \frac{dy}{dt}$$$$\frac{dy}{dt}=v=\sqrt{2gy}$$$$\Rightarrow u=-\frac{100\sqrt{2gy}}{y^2}$$$$=-\frac{100\sqrt{2\times 10\times 16}}{{16}^2}\approx -7m/s$$

Answered by MathematicalUser2357 last updated on 14/Nov/24

Commented by mr W last updated on 14/Nov/24

$$1ft=30.48cm$$

Commented by Frix last updated on 14/Nov/24

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