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Question Number 213821 by hardmath last updated on 17/Nov/24
Find:limx→0(sinxx)sinxx−sinx=?
Answered by mehdee7396 last updated on 17/Nov/24
limx→0(sinxx−1)sinxx−sinx=limx→0(sinx−xx)sinxx−sinx=−1⇒answer=e−1
Answered by lepuissantcedricjunior last updated on 20/Nov/24
limx→0(sinxx)sinxx−sinx=1FI=>limx→0(sinxx)sinxx−sinx=limx→0esinxln(sinxx)x−sinxdlsinxa`l′ordre3auvoisde0sinx=∑nk=0xkk!×fk(0)=x−x36+x(0)3limx→0e(x−x36)ln(1−x26)x−x+x36ordlln(1−t)a`l′ordre3auvoisde0donneln(1−t)=−t+t22−t33+t(0)3=>limx→0(sinxx)sinxx−sinx=limx→0e(x−x36)(−x26+x412)x36=limx→0e−x36x36=e−1..........................................................profcedricjunior.....
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