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Question Number 213939 by polymathAntunes last updated on 22/Nov/24

Commented by Frix last updated on 22/Nov/24

$$1.\mathrm{All}x\mathrm{on}\mathrm{one}\mathrm{side},$$$$\mathrm{constants}\mathrm{to}\mathrm{the}\mathrm{other}\mathrm{side}$$$$\frac{x}{4}+20=\frac{x}{3}\mid -\frac{x}{3}-20$$$$\frac{x}{4}-\frac{x}{3}=-20$$$$2.\mathrm{Common}\mathrm{denominator}\mathrm{and}\mathrm{add}$$$$4\times 3=12$$$$\frac{3x}{12}-\frac{4x}{12}=-20$$$$-\frac{x}{12}=-20$$$$3.\mathrm{Multiply}\mathrm{by}\mathrm{denominator}\mathrm{and}(-1)$$$$-\frac{x}{12}=-20\mid \times 12$$$$-x=-240\mid \times (-1)$$$$x=240$$

Answered by a.lgnaoui last updated on 22/Nov/24

$$\mathbf{Easy}!$$$$3\mathrm{x}+12\times 20=4\mathrm{x}\mathbf{x}=12\times 20$$$$\mathbf{x}=240$$$$\mathbf{v}\mathrm{e}\mathbf{rification}:\frac{240}{4}+20=80=\frac{240}{3}$$

Commented by polymathAntunes last updated on 22/Nov/24

Commented by a.lgnaoui last updated on 22/Nov/24

$$\mathbf{x}(\frac{1}{3}-\frac{1}{4})=20$$$$\frac{\mathbf{x}(4-3)}{12}=20\Rightarrow \mathbf{x}=20\times \frac{12}{4-3}=240$$$$$$$$\text{You can't use 'macro parameter character \#' in math mode}$$$$\mathit{R}\mathit{e}\mathit{m}\mathit{a}\mathit{r}\mathit{q}\mathit{u}\mathit{e}:$$$$\mathit{x}=\frac{\mathit{b}\mathit{d}\mathit{e}}{\mathit{d}\mathit{e}\mathit{t}\left|\begin{array}{c}\mathit{c}\mathit{a}\\ \mathit{d}\mathit{b}\end{array}\right|}$$

Commented by mr W last updated on 22/Nov/24

$$hehasevendifficultywithbasic$$$$additionandmultiplication$$$$operations.nowyouexplainhim$$$$withdeterminantofmatrix.agood$$$$try!:)$$

Answered by luj last updated on 22/Nov/24

$$\frac{x+80=}{4}\frac{x}{3}$$$$3x+240=4x$$$$240=x$$

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