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Question Number 214455 by hardmath last updated on 09/Dec/24

$$\mathrm{If}\mathrm{x}+\mathrm{y}+\mathrm{z}=\mathrm{xyz}$$$$\mathrm{Find}:$$$$\frac{\mathrm{x}(1-{\mathrm{y}}^2)(1-{\mathrm{z}}^2)+\mathrm{y}(1-{\mathrm{x}}^2)(1-{\mathrm{z}}^2)+\mathrm{z}(1-{\mathrm{x}}^2)(1-{\mathrm{y}}^2)}{2\mathrm{xyz}}$$

Commented by Ghisom last updated on 09/Dec/24

$$2$$

Commented by hardmath last updated on 09/Dec/24

$$\mathrm{Solution}\mathrm{please}...$$

Commented by Ghisom last updated on 09/Dec/24

$$\mathrm{you}\mathrm{have}\mathrm{to}\mathrm{expand}\mathrm{and}\mathrm{simply}\mathrm{use}$$$$xyz=x+y+z$$$$\mathrm{just}\mathrm{a}\mathrm{writing}\mathrm{exercise}$$

Commented by hardmath last updated on 09/Dec/24

$$\mathrm{my}\mathrm{undertan}...$$

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