Question and Answers Forum

All Questions      Topic List

Integration Questions

Previous in All Question      Next in All Question      

Previous in Integration      Next in Integration      

Question Number 214618 by kuldeep52 last updated on 13/Dec/24

$${\int }_0^{\mathrm{\Pi }/2}\frac{3\sqrt{\tan x}}{{(\sin x+\cos x)}^2}dx$$

Answered by Frix last updated on 14/Dec/24

$$3\int \frac{\sqrt{\tan x}}{{(\cos x+\sin x)}^2}dx\stackrel{[t=\sqrt{\tan x}]}{=}$$$$=6\underset{}{\int }\frac{t^2}{{(t^2+1)}^2}dt=3\int \frac{dt}{t^2+1}-3\int \frac{1-t^2}{{(t^2+1)}^2}dt=$$$$=3\arctan t-\frac{3t}{t^2+1}=$$$$=3\arctan \sqrt{\tan x}-\frac{3\sqrt{\cos x\sin x}}{\cos x+\sin x}+C$$$$\Rightarrow$$$$\mathrm{Answer}\mathrm{is}\frac{3\pi }{2}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com