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Question Number 21467 by nawroozdawry last updated on 24/Sep/17

$$\underset{1}{\stackrel{e}{\int }}\log xdx=$$

Answered by $@ty@m last updated on 24/Sep/17

$$I=\int \log x.1dx$$$$=\log x\int 1dx-\int \frac{1}{x}.xdx$$$$=x\log x-x+C$$$$\text{Missing left or extra right}$$$$=(e\log e-e)-(\log 1-1)$$$$=e-e-0+1$$$$=1$$

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