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Question Number 214770 by MathematicalUser2357 last updated on 19/Dec/24

$$\int {\sin }^{3}xdx=?$$

Answered by mr W last updated on 19/Dec/24

$$=-\int {\sin }^{2}xd\left(\cos x\right)$$$$=-\int (1-{\cos }^{2}x)d\left(\cos x\right)$$$$=-\cos x+\frac{{\cos }^{3}x}{3}+C✓$$

Commented by MathematicalUser2357 last updated on 19/Dec/24

$$thankyou$$

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