All Questions Topic List
Integration Questions
Previous in All Question Next in All Question
Previous in Integration Next in Integration
Question Number 214917 by Spillover last updated on 23/Dec/24
Answered by cemoosky last updated on 23/Dec/24
∫01∫01⋅⋅⋅∫01(x13+x23+⋅⋅⋅+xn3)dx1dx2⋅⋅⋅dxnforn=2018n∫01∫01⋅⋅⋅∫01(xn3)dx1dx2⋅⋅⋅dxn=n∫01(xn3)dxn=n[x44]01=n[(1)44−(0)44]=n[14]=2018[14]=20184=504.5
Commented by Spillover last updated on 24/Dec/24
great
Answered by Spillover last updated on 24/Dec/24
Terms of Service
Privacy Policy
Contact: info@tinkutara.com