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Question Number 215061 by mnjuly1970 last updated on 27/Dec/24
∫0∞∫0∞e−x2+y22sin(xy)dxdy=?
Answered by MrGaster last updated on 27/Dec/24
I=∫0∞∫0∞e−x2+y22sin(xy)dxdy=∫0π2∫0∞e−r22sin(r22sin2θ)rdrdθ=∫0π2sin2θ1+sin22θdθ=142ln(17+122)
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