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Question Number 215089 by golsendro last updated on 28/Dec/24

  log _2  x + log _3  (x+1) = 5    x = ?

log2x+log3(x+1)=5x=?

Answered by efronzo1 last updated on 28/Dec/24

   log _3 (x+1)−2 = 3−log _2 x    log _3 (((x+1)/9)) = log _2 ((8/x))    log _3 (1)= log _2 (1)=0    ((x+1)/9)=1 and (8/x)=1    x = 8

log3(x+1)−2=3−log2xlog3(x+19)=log2(8x)log3(1)=log2(1)=0x+19=1and8x=1x=8

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