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Question Number 215091 by mnjuly1970 last updated on 28/Dec/24

$$$$$$\underset{n=0}{\sum ^{\mathrm{\infty }}}{(-1)}^n\frac{{\mathrm{\Gamma }}^2(n+1)}{\mathrm{\Gamma }(2n+1)}=?$$$$---$$$$\beta (p,q)=\frac{\mathrm{\Gamma }\left(p\right)\mathrm{\Gamma }\left(q\right)}{\mathrm{\Gamma }(p+q)}$$

Answered by MrGaster last updated on 28/Dec/24

Commented by mnjuly1970 last updated on 29/Dec/24

$$thanksalotsir$$

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