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Question Number 215114 by issac last updated on 29/Dec/24

	Answered by TonyCWX08 last updated on 29/Dec/24

	$\oint = I n t e g r a l o v e r a c l o s e d p a t h$ $\subset \int \int \supset= I n t e g r a l o v e r a c l o s e d s u r f a c e$ $\subset \int \int \int \supset= I n t e g r a l o v e r a c l o s e d r e g i o n i n 3 D s p a c e .$
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