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Question Number 215255 by Rasheed.Sindhi last updated on 01/Jan/25
a,b,carepythagoreantriplesForthefollowingvalues:abc51213a2=b+c⇒52=12+13=25abc4510121013a2=b+c⇒452=1012+1013=2025⇒452=1012+1013=2025HAPPYNEWYEAR!
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