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Question Number 215404 by ajfour last updated on 05/Jan/25
∫ax1+4x2a2−x2dx=?
Answered by Ghisom last updated on 06/Jan/25
∫1+4x2a2−x2dx=E(arcsinxa∣−4a2)+C
Commented by ajfour last updated on 07/Jan/25
Thanks.Elliptic?
Commented by Ghisom last updated on 07/Jan/25
yes
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