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Question Number 215418 by BaliramKumar last updated on 06/Jan/25

Answered by TonyCWX08 last updated on 06/Jan/25

$$Let$$$$Sumofcorrectnumbers=x$$$$Sumofsquareofcorrectnumbers=y$$$$$$$$\frac{x+10}{25}=42$$$$x=42\left(25\right)-10=1040$$$$$$$$\sqrt{\frac{y+{10}^2}{25}-{42}^2}=5\Rightarrow y=44625$$$$$$$$Newmean$$$$=\frac{1040+210}{25}=50$$$$$$$$NewS.D$$$$=\sqrt{\frac{44625+{210}^2}{25}-{50}^2}=\sqrt{1049}$$

Commented by BaliramKumar last updated on 06/Jan/25

$$thanks$$

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