simplify a−{b^(c−b) +⟨(b^(c−b) )^2 +((a/2))^2 ⟩+(a/2)}+c^(ab−c) −c^(a−c)


Question and Answers Forum

All Questions Topic List
None Questions
Previous in All Question Next in All Question
Previous in None Next in None
Question Number 215504 by alephnull last updated on 08/Jan/25
$simplify a−{b^(c−b) +⟨(b^(c−b) )^2 +((a/2))^2 ⟩+(a/2)}+c^(ab−c) −c^(a−c)$
$simplify a - {b^{c - b} + ⟨ {(b^{c - b})}^{2} + {(\frac{a}{2})}^{2} ⟩ + \frac{a}{2}} + c^{a b - c} - c^{a - c}$
	Answered by MrGaster last updated on 08/Jan/25
	$simplify a−{b^(c−b) +⟨(b^(c−b) )^2 +((a/2))^2 ⟩+(a/2)}+c^(ab−c) −c^(a−c) a−b^(c−a) −(b^(2(c−a)) +((a/2))^2 )−(a/2)+c^(ab−c) −c^(a−c) a−b^(c−a) −b^(2(c−a)) −(a^2 /4)−(a/2)+a^(ab−c) −c^(e−c) (a−(a^2 /4)−(a/2))−b^(c−b) −b^(2(c−b)) +c^(ab−c) −c^(a−c) (((2a−a^2 )/4))−b^(c−b) −b^(2(c−a)) +e^(ab+c) −c^(a−c) ((2a−a^2 )/4)−b^(c−b) −b^(2(c−a)) +e^(ab+c) −c^(a−c) ✓$
	$simplify a - {b^{c - b} + ⟨ {(b^{c - b})}^{2} + {(\frac{a}{2})}^{2} ⟩ + \frac{a}{2}} + c^{a b - c} - c^{a - c}$ $a - b^{c - a} - (b^{2 (c - a)} + {(\frac{a}{2})}^{2}) - \frac{a}{2} + c^{a b - c} - c^{a - c}$ $a - b^{c - a} - b^{2 (c - a)} - \frac{a^{2}}{4} - \frac{a}{2} + a^{a b - c} - c^{e - c}$ $(a - \frac{a^{2}}{4} - \frac{a}{2}) - b^{c - b} - b^{2 (c - b)} + c^{a b - c} - c^{a - c}$ $(\frac{2 a - a^{2}}{4}) - b^{c - b} - b^{2 (c - a)} + e^{a b + c} - c^{a - c}$ $\frac{2 a - a^{2}}{4} - b^{c - b} - b^{2 (c - a)} + e^{a b + c} - c^{a - c} ✓$
	Commented by alephnull last updated on 09/Jan/25

	$t h N k s y o u$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum