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Question Number 215527 by alephnull last updated on 09/Jan/25

$$t_{33}^{\prime }ab+t_{00}^{\prime }ab=?$$$$$$$$\mathrm{Clearing}\mathrm{up}\mathrm{defintions}:$$$$t_{33}^{\prime }a=(a-\sqrt{36})\times 3$$$$t_{00}^{\prime }a=(a-\sqrt{36})\times 0$$$$t^{\prime }a=a-\sqrt{36}$$$$t^{\prime }a=‘‘{\mathrm{transformation}}^{″}\mathrm{of}a$$

Answered by MrGaster last updated on 10/Jan/25

$${\acute{t}}_{33}a=(a-6)\times 3=3a-18$$$${\acute{t}}_{00}a=(a-6)\times 0=0$$$$t^{\prime }a=a-6$$$$\Rightarrow t_{33}^{\prime }ab+t_{00}^{\prime }ab=(3a-18)b+0$$$$=3ab-18b$$$$\Rightarrow t_{33}^{\prime }ab+t_{00}^{\prime }ab=3ab-18b✓$$

Commented by alephnull last updated on 10/Jan/25

$$thankyousirwhatwoulditbewiththenotationof{t}^{\prime }?$$

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