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Question Number 215943 by sitholenonto last updated on 22/Jan/25

Answered by MathematicalUser2357 last updated on 23/Jan/25

$$\mathrm{Q}.2.1$$$$\sqrt{{(30-10\times \tan 60°)}^2+{10}^2}$$$$16.14836✓$$$$\mathrm{Q}.2.2$$$$\sqrt{{(200-400\times \cos 70°)}^2+{(200\times \tan 60°+400\times \sin 70°)}^2}$$$$725.04623✓$$$${\tan }^{-1}\left(\frac{200\times \tan 60°+400\times \sin 70°}{200-400\times \cos 70°}\right)/\left(1°\right)$$$$85\left(°\right)✓$$$$\mathrm{Q}.2.3(\mathrm{Following}\mathrm{Q}.2.2)$$$$\frac{(200-400\times \cos 70°)\times 20}{{10}^3}$$$$1.263839✓$$

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