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Question Number 215963 by RoseAli last updated on 23/Jan/25
Answered by Frix last updated on 23/Jan/25
∫(cosx+sinx)n(1−2sin2x)dx==∫(cosx+sinx)n(sin2x−cos2x)dx==∫(cosx+sinx)n+1(sinx−cosx)dx==1n+2(cosx+sinx)n+2+C
Commented by mehdee7396 last updated on 23/Jan/25
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