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Question Number 216055 by efronzo1 last updated on 26/Jan/25
limx→0sin22xcosx3−cosx4=?
Answered by golsendro last updated on 27/Jan/25
=limx→04cos2x(1−cos2x)cosx3−cosx4=8.limx→01−cosxcosx3−cosx4Letcosx=t12=8limt→11−t12t4−t3=8limt→1(1−t)(t11+t10+...+1)t3(t−1)=−8.(12)=−96
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