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Question Number 216183 by MATHEMATICSAM last updated on 29/Jan/25
Answered by A5T last updated on 29/Jan/25
=a3−a2(b+c)+b3+c3+2abc−b2(a+c)−c2(a+b)=a2(a−b−c)+b3+c3+2bc(a−b−c+b+c)−b2(a−b−c+b+2c)−c2(a−b−c+2b+c)=(a−b−c)(a2+2bc−b2−c2)=(a−b−c)(a−b+c)(a+b−c)
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