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Question Number 216312 by MATHEMATICSAM last updated on 03/Feb/25
Ifab2+bc2+ca2=0thenfind(ab+bc)+(bc+ca)+(ca+ab)+2.
Answered by Rasheed.Sindhi last updated on 03/Feb/25
ab2+bc2+ca2=0ab2abc+bc2abc+ca2abc=0bc+ca+ab=02(bc+ca+ab)=0bc+ca+ab+bc+ca+ab=0(ab+bc)+(bc+ca)+(ca+ab)+2=2
Answered by som(math1967) last updated on 03/Feb/25
2ab+2bc+2ca+2=2a2c+2b2a+2c2babc+2=2(ab2+bc2+ca2)abc+2=2×0abc+2=2
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