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Question Number 216748 by sniper237 last updated on 17/Feb/25

$$Find{\int }_{-1}^{1}ln\mid \mathrm{\Gamma }(\frac{1}{2}+it)\mid dt$$

Answered by issac last updated on 18/Feb/25

$${\mathrm{can}}^{\prime }\mathrm{t}\mathrm{simplify}$$$$\mathrm{function}\ln (\mid \mathrm{\Gamma }(\mathit{i}t+\frac{1}{2})\mid )$$$$\mathrm{but}...\mathrm{Approximatly}...$$$${\int }_{-1}^1\ln (\mid \mathrm{\Gamma }(\mathit{i}t+\frac{1}{2})\mid )\mathrm{d}t\approx 0.136478....$$

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