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Question Number 217015 by hardmath last updated on 26/Feb/25

$$\mathrm{If}$$$$\mathrm{f}(2\mathrm{x}+1)=3\mathrm{x}+5$$$$\mathrm{Find}$$$$\mathrm{f}\left(\mathrm{x}\right)=?$$

Answered by Rasheed.Sindhi last updated on 26/Feb/25

$$let2\mathrm{x}+1=\mathrm{y}$$$$\mathrm{x}=\frac{\mathrm{y}-1}{2}$$$$\mathrm{f}\left(\mathrm{y}\right)=3\left(\frac{\mathrm{y}-1}{2}\right)+5$$$$=\frac{3\mathrm{y}-3+10}{2}$$$$\mathrm{f}\left(\mathrm{x}\right)=\frac{3\mathrm{x}+7}{2}$$

Answered by Hanuda354 last updated on 27/Feb/25

$$f(2x+1)=3x+5$$$$f(2x+1)=\frac{3}{2}(2x+1)+\frac{7}{2}$$$$f\left(x\right)=\frac{3}{2}x+\frac{7}{2}$$$$f\left(x\right)=\frac{3x+7}{2}$$

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