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Question Number 217140 by peter frank last updated on 02/Mar/25

if a, b, c are three digits, abc and bca are two numbers. where abc +cba = 444, b =2. find the value of a+b+c.

Answered by Rasheed.Sindhi last updated on 02/Mar/25

$$\overline{abc}+\overline{cba}=444$$$$\overline{a2c}+\overline{c2a}=444$$$$(100a+20+c)+(100c+20+a)=444$$$$101a+101c=404$$$$a+c=4$$$$a+b+c=4+2=6$$

Commented by peter frank last updated on 02/Mar/25

$$\mathrm{thank}\mathrm{you}$$

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